Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Explain solution RD Sharma class 12 Chapter 27 Striaght Line in Space Exercise Very Short Answer question 18

Explain solution RD Sharma class 12 Chapter 27 Striaght Line in Space Exercise Very Short Answer question 18

Answers (1)

Answer:

Required answer is   \frac{-1}{\sqrt{6}}, \frac{1}{\sqrt{6}}, \frac{2}{\sqrt{6}}

Hint:

Use the equation of a line in space.

Given:

\frac{4-x}{3}=\frac{y+3}{3}=\frac{z+2}{6}

Solution:

We have,

\frac{4-x}{3}=\frac{y+3}{3}=\frac{z+2}{6}

The equation of the given line can be rewritten as,

\frac{x-4}{-3}=\frac{y+3}{3}=\frac{z+2}{6}

The direction ratios of the line parallel to the given line are proportional to  -3,3,6

The direction cosines of the line parallel to the given line are proportional to

\begin{aligned} &\frac{-3}{\sqrt{(-3)^{2}+3^{2}+6^{2}}}, \frac{3}{\sqrt{(-3)^{2}+3^{2}+6^{2}}}, \frac{6}{\sqrt{(-3)^{2}+3^{2}+6^{2}}} \\ & \end{aligned}

=\frac{-1}{\sqrt{6}}, \frac{1}{\sqrt{6}}, \frac{2}{\sqrt{6}}

Posted by

infoexpert27

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE Class 12 result verification 2024 application out at cbse.gov.in; last date, fees
anam-khan

CBSE results 2024 later for 102 students over fake certificates; board issues show cause notice
anam-khan

What after CBSE Class 12 results 2024? From CUET UG to JEE Advanced, all you need to know

Latest Question