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  • Explain solution RD Sharma class 12 Chapter 27 Striaght Line in Space Exercise Very Short Answer question 19

Explain solution RD Sharma class 12 Chapter 27 Striaght Line in Space Exercise Very Short Answer question 19

Answers (1)

Answer:  \left ( -2,4,-5 \right )

Required answer is 

Hint:

Use the equation of a line in space.

Given:

Point  \frac{x+2}{3}=\frac{y-4}{-5}=\frac{z+5}{6}

Line  \frac{x+3}{3}=\frac{y-4}{-5}=\frac{z+8}{6}

Solution:

The equation of the given line is

\frac{x+3}{3}=\frac{y-4}{-5}=\frac{z+8}{6}

Since the required line is parallel to the given line, the direction ratios of the required line are proportional to 3,-5,6

Hence the Cartesian equation of the line passing through the point  \left ( -2,4,-5 \right )  and parallel to a vector having direction ratios proportional to  3,-5,6  is

\frac{x+2}{3}=\frac{y-4}{-5}=\frac{z+5}{6}

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