Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Need Solution for R.D. Sharma Maths Class 12 Chapter 27 Straight Line in Space Exercise 27.2 Question 18 Maths Textbook Solution.

Need Solution for R.D. Sharma Maths Class 12 Chapter 27 Straight Line in Space  Exercise 27.2 Question 18  Maths Textbook Solution.

Answers (1)

Answer: The equation of the given question will be \vec{r}=(\hat{i}+2 \hat{j}-4 \hat{k})+\lambda(2 \hat{i}+3 \hat{j}+6 \hat{k})

Given: Determine the equation of the line passing through the point (1,2,-4) and perpendicular to the two lines;

\frac{x-8}{3}=\frac{y+9}{-16}=\frac{3-0}{7} &\frac{x-15}{3}=\frac{y-29}{8}=\frac{3-5}{5}   

Hint:  \vec{r}=\vec{a}+\lambda \vec{b}(for showing parallel lines)

Solution:

Direction\: ratio _{1}=3 i-16 \hat{j}+7 \hat{k}

Direction \: ratio _{2}=3 i-8 \hat{j}-5 \hat{k}

\begin{aligned} &\therefore D R_{1} \times D R_{2}=\left|\begin{array}{ccc} \hat{i} & \hat{j} & \hat{k} \\ 3 & -16 & 7 \\ 3 & -8 & -5 \end{array}\right| \\ &=24 \hat{i}+36 \hat{j}+72 \hat{k} \\ &=12(2 \hat{i}+3 \hat{j}+6 \hat{k}) \\ &\therefore D R=2,3,6 \\ &\vec{r}=(\hat{i}+2 \hat{j}-4 \hat{k})+\lambda(2 \hat{i}+3 \hat{j}+6 \hat{k}) \end{aligned}

The equation will be \vec{r}=(\hat{i}+2 \hat{j}-4 \hat{k})+\lambda(2 \hat{i}+3 \hat{j}+6 \hat{k})

Posted by

infoexpert21

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE Class 12 result verification 2024 application out at cbse.gov.in; last date, fees
anam-khan

CBSE results 2024 later for 102 students over fake certificates; board issues show cause notice
anam-khan

What after CBSE Class 12 results 2024? From CUET UG to JEE Advanced, all you need to know

Latest Question