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  • Need solution for RD Sharma Maths Class 12 Chapter 27 Straight Line of Space Excercise Very Short Anwer Question 10

Need solution for RD Sharma Maths Class 12 Chapter 27 Straight Line of Space Excercise Very Short Anwer Question 10

Answers (1)

Answer:

Required answer is  \frac{3}{7}, \frac{2}{7}, \frac{-6}{7}

Hint:

Use equation of a line in space.

Given:

Cartesian equations are  2 x=3 y=-z

Solution:

We have,

2 x=3 y=-z

The equation of the given line can be rewritten as,

\begin{aligned} &\frac{x}{\frac{1}{2}}=\frac{y}{\frac{1}{3}}=\frac{z}{-1} \\ & \end{aligned}

\frac{x}{3}=\frac{y}{2}=\frac{z}{-6}

The direction ratios of the line parallel to AB are proportional to  3,2,-6

The direction cosines of the line parallel to AB are proportional to

\begin{aligned} &\frac{3}{\sqrt{3^{2}+2^{2}+(-6)^{2}}}, \frac{2}{\sqrt{3^{2}+2^{2}+(-6)^{2}}}, \frac{-6}{\sqrt{3^{2}+2^{2}+(-6)^{2}}} \\ & \end{aligned}

=\frac{3}{7}, \frac{2}{7}, \frac{-6}{7}

Posted by

infoexpert27

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