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Please Solve RD Sharma Class 12 Chapter 27 Straight Line in Space Exercise Fill in the blanks Question 3 Maths Textbook Solution.

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Answer :  \vec{r}=3 \hat{\imath}+4 \hat{\jmath}-7 \hat{k}+\lambda(-2 \hat{\imath}-5 \hat{\jmath}+13 \hat{k})

Hint : Use the vector equation

Given : Point (3 , 4 , -7) and ( 1 , -1 , 6)

Solution : Given points are

                  \begin{aligned} &\mathrm{A}(3,4,-7), \mathrm{B}(1,-1,6) \\ & \end{aligned}

                  \vec{A}=3 \hat{\imath}+4 \hat{\jmath}-7 \hat{k} \\

                  \vec{B}=\hat{i}-\hat{\jmath}+6 \hat{k}

                 ∴  vector equation

                \begin{aligned} \vec{r} &=(3 \hat{\imath}+4 \hat{\jmath}-7 \hat{k})+\lambda[\hat{\imath}-\hat{\jmath}+6 \hat{k}-(3 \hat{\imath}+4 \hat{\jmath}-7 \hat{k})] \\ & \end{aligned}

                =3 \hat{\imath}+4 \hat{\jmath}-7 \hat{k}+\lambda(-2 \hat{\imath}-5 \hat{\jmath}+13 \hat{k})

 

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