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  • Need solution for RD Sharma Maths Class 12 Chapter 27 Straight Line of Space Excercise Fill in the blanks Question 11

Need solution for RD Sharma Maths Class 12 Chapter 27 Straight Line of Space Excercise Fill in the blanks Question 11

Answers (1)

Answer :  \frac{x-2}{1}=\frac{y-1}{1}=\frac{z+1}{\sqrt{2}}

Hint :  Compare the given equation

Given :  ( 2 , 1 , -1 ) and making angles   \frac{\pi}{3}, \frac{\pi}{3} \text { and } \frac{\pi}{4}

Solution : So comparing with general Cartesian from of Eq.

                  a = 2 , b =1 , c = -1

                  another line passing through P ( 1 , 1 , 2)

                  we can assume it as position   vector and parallel to given  line so normal vector will be same .

                 Eq. of line is given by   \frac{x-x_{1}}{l}=\frac{y-y_{1}}{m}=\frac{z-z_{1}}{n}

                 Here   \begin{gathered} l ,m, n(1,1, \sqrt{2}) \\ \end{gathered}

                 \frac{x-2}{1}=\frac{y-1}{1}=\frac{z+1}{\sqrt{2}}

                                  

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