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Need solution for RD Sharma maths class 12 chapter 27 Straight Line in Space exercise Multiple choice question 11

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Answer: Correct answer is A.

Hint: Use vector dot product.

Given: x,y and z are 12, 4 and 3

Solution: Let the line segment be represented in vector form as \vec{a}=a_{1} \vec{\imath}+a_{2} \vec{\jmath}+a_{3} \vec{k}  vector along co-ordinate axes are\vec{i}, \vec{j}, \vec{k} vector along given that projection of \vec{a} \text { on } x-\text { axis is } 12, that with y-\text { axis is } 4  and

that with z-\text { axis is } 3.


\begin{aligned} &\Rightarrow \vec{a} \cdot \vec{l}=12 \\\\ &\Rightarrow a_{1}=12 \end{aligned}

Similarly a_{2}=4, a_{3}=3

\therefore \vec{a}=12 \vec{\imath}+4 \vec{\jmath}+3 \vec{k}

The line segment of the length |\vec{a}|=\sqrt{144+16+9} \Rightarrow 13  and the direction cosines of the line segment are <13, \frac{12}{13}, \frac{4}{13}, \frac{3}{13}>

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