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Provide Solution for RD Sharma Class 12 Chapter 27 Straight Line in Space Exercise Very Short Answer Question 22

Answers (1)

Answer:

Required answer is  \vec{r}=(3 \hat{i}+4 \hat{j}+5 \hat{k})+\lambda(2 \hat{i}+2 \hat{j}-3 \hat{k})

Hint:

Use equation of a line in space.

Given:

Point  \left ( 3,4,5 \right )  and parallel vector  2 \hat{i}+2 \hat{j}-3 \hat{k}

Solution:

The line is passing through the point  \left ( 3,4,5 \right )  through the point having position vector is  \vec{a}=3 \hat{i}+4 \hat{j}+5 \hat{k}  and parallel to the vector  \vec{b}=2 \hat{i}+2 \hat{j}-3 \hat{k}

\begin{aligned} &\vec{r}=\vec{a}+\lambda \vec{b} \\ & \end{aligned}

\vec{r}=(3 \hat{i}+4 \hat{j}+5 \hat{k})+\lambda(2 \hat{i}+2 \hat{j}-3 \hat{k})

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