Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
Filter By
Clear Filter

All Questions

3.8 The conductivity of 0.20 M solution of KCl at 298 K is 0.0248 S cm–1. Calculate its molar conductivity.

We know that the molar conductivity of a solution is defined as:- 

                                                 \Lambda _M\ = \frac{\kappa }{C}

Putting the value of conductivity and concentration in the above equation:- 

                                                   \Lambda _M\ = \frac{0.0248\times1000 }{0.20} = 124\ Scm^2\ mol^{-1}

View Full Answer(1)
Posted by

Devendra Khairwa

filter_img