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A sum of money under compound interest doubles itself in 4 years. In how many years will it become 16 times itself? 

 

Option: 1

12 years


Option: 2

16 years


Option: 3

8 years


Option: 4

None of these


let p be the principle amount

After 4 years, the amount is 2p.

Using the compoubd intrest formula: 2p=p(1+r)4 

Divide both sides by p:2=(1+r)4

Take the fourth root of both sides: 1+r=2 1/4

Solve for r: r=2 1/4-1 

It will take 16 years 

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Posted by

Khushi singh

A certain loan amounts, under compound interest, compounded annually earns an interest of Rs.1980 in the second year and Rs.2178 in the third year. How much interest did it earn in the first year?

Option: 1

Rs.1600


Option: 2

Rs.1800


Option: 3

 Rs.1900


Option: 4

None of these

 


1800

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Posted by

Guru G

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Find the compound interest on Rs. 5000 in 2 years at 4% per annum, the interest being compounded half yearly.

 

Option: 1

R 412.16


Option: 2

R 312.16


Option: 3

R 400.16


Option: 4

R 420.16

 


412.16

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Posted by

NARENDAR

14. Find the present value (in Rs.) of Rs.3000 due after 5 years at 10% p.a. simple interest.

Option: 1

1500


Option: 2

1800


Option: 3

2000


Option: 4

2500


Option a 1500

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Posted by

Madhavee vijay kadam

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An athlete runs 200 meters race in 24 seconds. His speed is

 

Option: 1

20 km/hr


Option: 2

24 km/hr


Option: 3

28.5 km/hr


Option: 4

30 km/hr


28.5

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Posted by

Guru G

The distance between two stations A and B is 440 km. A train starts at 4 p.m. from A and move towards B at an average speed of 40 km/hr. Another train starts B at 5 p.m. and moves towards A at an average speed of 60 km/hr. How far from A will the two trains meet and at what time?

Option: 1

200,8 p.m.


Option: 2

300,9 p.m.


Option: 3

200,9 p.m.


Option: 4

300,8 p.m.


200,9

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Posted by

Guru G

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PQ is a tunnel. A dog sits at the distance of 5/ 11 of PQ from P. The train whistle coming from any end of the tunnel would make the dog run. If a train approaches P and dog runs towards P the train would hit the dog at P. If the dog runs towards Q instead, it would hit the dog at Q. Find ratio of speed of train and dog?

 

Option: 1

5:2


Option: 2

16:5


Option: 3

11:1


Option: 4

34:3


Option 3 - 11:1

########            P____5_____¶______6_____Q

"¶" is the dog located inside the tunnel PQ and #####... is a train approaching to it. 

Case 1 - Dog decides to reach point P 

Distance covered by Dog - 5 parts and train reaches at P

Case 2 - Dog decides to run towards point Q

At the time train reaches to point P, the dog covers 5 parts in direction of Q. Now the left out part covered by dog will be 1 part towards Q .

At the time dog covers 1 part and reaches Q, train covers whole 11 parts of tunnel and reaches from P to Q. 

So, 11 part of train is eual to the 1 part covered by the dog to reach Q. 

Ratio of their speeds - Train:Dog = 11:1  

 

 

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Posted by

Vaibhavi Gupta

The sum of $\overline{2} .75$ and $\overline{3} .78$ is :

Option: 1

$\overline{5} .53$


Option: 2

$\overline{4} .53$


Option: 3

$\overline{1} .53$


Option: 4

$\overline{1} .03$


B

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Posted by

Karina kishor kadam

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The simplification of $(0 . \overline{6}+0 . \overline{7}+0 . \overline{8}+0 . \overline{3})$ yields the result:

Option: 1

$10 / 9$


Option: 2

$20 / 9$


Option: 3

2. $\overline{35}$


Option: 4

$23 / 5$


B

 

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Posted by

Karina kishor kadam

Spin only magnetic moment of an octahedral complex of \mathrm{Fe}^{2+} in the presence of a strong field ligand in BM is :
Option: 1 4.89
Option: 2 4.89
Option: 3 4.89
Option: 4 4.89
Option: 5 2.82
Option: 6 2.82
Option: 7 2.82
Option: 8 2.82
Option: 9 0
Option: 10 0
Option: 11 0
Option: 12 0
Option: 13 3.46
Option: 14 3.46
Option: 15 3.46
Option: 16 3.46

Electionic configuration of  \mathrm{Fe}^{2+}=[\mathrm{Ar}] 3 \mathrm{~d}^{6}

In the preserce of a strong field ligand, pairing will take place

Thus there are no unpaired electrons and the spin only magnetic moment is zero.

Hence, the correct answer is option (3)

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Posted by

sudhir.kumar

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