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  • 10 mL of 2M  solution is added to 200 mL of 0.5M of <img alt="NaOH" src="https://entrancecorner.oncodecogs.com

10 mL of 2M NaOH solution is added to 200 mL of 0.5M of NaOH solution. What is the final concentration?

Option: 1

0.57(M)


Option: 2

5.7(M)


Option: 3

11.4(M)


Option: 4

1.14(M)


Answers (1)

best_answer

We know:

molarity = moles / volume(L)

Thus, for volume = 10ml and molarity = 2M, we have:

moles = (2 x 10) / 1000
          = 0.02 moles

Again, for volume = 200ml and molarity = 0.5M, we have:

moles = (0.5 x 200) / 1000
          = 0.1 moles

Therefore total number of moles of NaOH = 0.12
and total volume = 200 + 10 = 210ml

Thus, final concentration = (0.12/210) x 1000
                                     = 0.57M

Therefore, Option(1) is correct

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