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16 identical cells with emf 2V and internal resistance 1\Omega are connected in a row and 8 such rows are connected together. Then potential difference across an external resistance of 4\Omega is

Option: 1

\frac{16}{32}V


Option: 2

\frac{32}{3}V


Option: 3

\frac{64}{3}V


Option: 4

18V


Answers (1)

best_answer

As we learnt

Potential difference across load -

V=iR

-

i=\frac{mnE}{mR+nr}=\frac{16*8*2}{16*1+8*4}= \frac{16}{3}A

P.D. across external resistance is V=\frac{16}{3}*4V=\frac{64}{3}V

Posted by

Ajit Kumar Dubey

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