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  • 3 moles of an ideal monoatmic gas performs a cycle as shown in the fig. The gas temperatures <img alt="\mathrm{T}_{1}={400 \mathrm{~K}, \mathrm{~T}_{2}=}{800 \mathrm{~K}, \mathrm{~T}_{3}}= {24

3 moles of an ideal monoatmic gas performs a cycle as shown in the fig. The gas temperatures \mathrm{T}_{1}={400 \mathrm{~K}, \mathrm{~T}_{2}=}{800 \mathrm{~K}, \mathrm{~T}_{3}}= {2400 \mathrm{~K}, \mathrm{~T}_{4}=}{1200 \mathrm{~K}}.  What will be the net work done.

Option: 1

20 \mathrm{~J}


Option: 2

20000 \mathrm{~J}


Option: 3

200 \mathrm{~J}


Option: 4

2000 \mathrm{~J}


Answers (1)

best_answer

\mathrm{W}_{A B}=\mathrm{C}_{C D}=0, because process is isochoric.

\mathrm{W_{A D}=n R \Delta T=3 R\left(T_{A}-T_{B}\right)=3 \times 8.31(2400-800)=39884}

\mathrm{\therefore \quad Total\, work\, done \mathrm{W}_{\mathrm{AD}}+\mathrm{W}_{\mathrm{BC}}=39888-19944=20 \times 10^{3} \mathrm{~J}=19944}
\mathrm{\approx 20 \times 10^{3} \mathrm{~J}}

Posted by

HARSH KANKARIA

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