5 L of an alkane requires 25 L of oxygen for its complete combustion. If all volumes are measured at constant temperature and pressure, the alkane is :
Ethane
Propane
Butane
Isobutane
Combustion of alkane
From the above reaction,
No. of moles of alkane =1
From ideal gas equation,
PV=nRT
At same temperature and pressure,
Given:-
Volume of alkane =5L
Volume of oxygen =25L
From equation (1), we have
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