A light rod of length 2 m is suspended from the ceiling horizontally by means of two vertical wires of equal length tied to its ends. One of the wires is made of brass and its area of cross section 0.29*10-4 m^2 and the other is of steel of cross section 0.1*10^-4 m^2. In order to have equal stress in the two wires, a weight should be hung from the end A at a distance of. Study 40% syllabus and score up to 100% marks in JEE
@Roshni Afrin
sir could u plz explain me ... why u wrote Tx=T(2-x)
Let the point c is at a distance x from B(Si). Then the distance from A(Brass)=(total length of rod-x)=(2-x)