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  • A 6.50 molal solution of  has a density of 1.89 g cm -3. The molarity of the solution is _____ mol dm -3. (Round off to the Nearest Integer). [Atomic mas

A 6.50 molal solution of KOH(aq.) has a density of 1.89 g cm -3. The molarity of the solution is _____ mol dm -3. (Round off to the Nearest Integer). [Atomic masses : K : 39.0 \; u ; O : 16.0 \; u ; H : 1.0\; u ]  
 

Answers (2)

best_answer

6.5 molal KOH = 1000g solvent has 6.5 moles KOH

so wt of solute = 6.5 × 56 = 364 g

wt of solution = 1000 + 364 = 1364

\text { Volume of solution }=\frac{1364}{1.89} \mathrm{~m} \ell

\text { Molarity }=\frac{\text { mole of solute }}{\mathrm{V}_{\text {solution }} \text { in Litre }}

\begin{aligned} \text { Molarity } &=\frac{6.5 \times 1.89 \times 1000}{1364} \\ &=9.00 \end{aligned}

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