Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • A ball is projected with kinetic energy E, at an angle of to the horizontal. The kinetic energy of

A ball is projected with kinetic energy E, at an angle of 60^{\circ} to the horizontal. The kinetic energy of this ball at the highest point of its flight will become :

Option: 1

Zero


Option: 2

\mathrm{\frac{E}{2}}


Option: 3

\mathrm{\frac{E}{4}}


Option: 4

\mathrm{E}


Answers (1)

best_answer

\mathrm{u_{x}=u\cos 60\degree=\frac{u}{2}}

\mathrm{u_{y}=u\cos 60\degree=\frac{\sqrt{3}u}{2}}

\mathrm{E=\frac{1}{2}mu^{2}}

At the highest point ,

\mathrm{Kinetic \: energy=\frac{1}{2}mv^{2}}

                            \mathrm{=\frac{1}{2}m\left ( u\cos 60\degree \right )^{2}}

                            \mathrm{=\frac{1}{4}\left ( \frac{1}{2}mu^{2} \right )}

                            \mathrm{=\frac{1}{4}\left ( E \right )=\frac{E}{4}}

Hence 3 is correct option

Posted by

Gautam harsolia

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2025 Session 2 City Slip (OUT) Live: NTA exam city intimation slip link available; admit card date
anam-khan

AESL expands Aakash Digital 2.0 to offer AI-powered coaching for NEET, JEE, Olympiads
anam-khan

Bihar Board extends BSEB Super 50 free coaching application last date to March 26

Latest Question