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A ball of mass \mathrm{ \mathrm{m}} is thrown vertically upward. Another ball of mass \mathrm{ 2 \mathrm{~m}} is thrown at an angle \mathrm{ \theta} with the vertical. Both the balls stay in air for the same period of time. The ratio of the heights attained by the two balls respectively is \mathrm{ \frac{1}{x}.} The value of \mathrm{x} is ________.

Option: 1

1


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

\rightarrowTlime of flight depends on vertical speed.

\mathrm{T=\frac{2 u_y}{g}=\frac{2 u \sin \theta}{g}}
\rightarrowAs the time of flight is same for both of them, the maximum vertical hight will be same.

\mathrm{\Rightarrow \therefore \frac{1}{x} =1 }

\mathrm{x =1}



 

Posted by

jitender.kumar

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