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A beam of light of wavelength 600 \mathrm{~nm} from a distant source falls on a single slit 1.00 \mathrm{~mm} wide and the resulting diffraction pattern is observed on a screen 2 \mathrm{~m} away. The distance between the first dark fringes on either side of the central bright fringe is:

Option: 1

1.2 cm


Option: 2

1.2 mm


Option: 3

2.4 cm


Option: 4

2.4 mm


Answers (1)

best_answer

\mathrm{ \lambda=600 \mathrm{~nm}=6 \times 10^{-7} \mathrm{~m}, \mathrm{a}=1 \mathrm{~mm}=10^{-3} \mathrm{~m}, \mathrm{D}=2 \mathrm{~m} }

Distance between the first dark fringes on either side of central bright fringe = width of central maximum

\mathrm{ =\frac{2 \lambda \mathrm{D}}{\mathrm{a}}=\frac{2 \times 6 \times 10^{-7} \times 2}{10^{-3}}=24 \times 10^{-4} \mathrm{~m}=2.4 \mathrm{~mm} }

Posted by

Sanket Gandhi

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