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  • A bike rider covers half the distance at 10 m/s speed; then the remaining distance he covers  with 20 m/s for the half time and another half time at 25 m/s speed; the mean speed of t

A bike rider covers half the distance at 10 m/s speed; then the remaining distance he covers  with 20 m/s for the half time and another half time at 25 m/s speed; the mean speed of the bike rider over the whole motion is  \frac{x}{13}ms^{-1}; the value of x is 

Option: 1

400


Option: 2

30


Option: 3

180

 


 


Option: 4

200


Answers (1)

best_answer

Let us assume that the total distance covered is “x” m 

and for the first half distance time taken is t_{1}=\frac{\frac{x}{2}}{10}

And for another half distance 

 \frac{x}{2}=\frac{20t_{2}}{2}+\frac{25t_{2}}{2}

Time is taken for the next half distance 

 t_{2}=\frac{x}{45}

The mean speed will be  = \frac{x}{t_{1}+t_{2}}

Therefore mean speed   = \frac{x}{\frac{x}{20}+\frac{x}{45}}

From here we can see that the mean speed will be   = \frac{180}{13}ms^{-1}

Therefore the value of x is 180 

Posted by

shivangi.bhatnagar

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