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  • A block of ice of mass at temperature <img alt="0^{\circ} \mathrm{C}" src="/latex-image/?0%5E%7B%5Ccirc%7D%20%5Cmathrm%7B

A block of ice of mass 120 \mathrm{~g} at temperature 0^{\circ} \mathrm{C} is put in 300 \mathrm{~g} of water at 25^{\circ} \mathrm{C}. The \mathrm{xg} of ice melts as the temperature of the water reaches 0^{\circ} \mathrm{C}. The value of \mathrm{x} is___________ [Use specific heat capacity of water =4200 \mathrm{Jkg}^{-1} \mathrm{~K}^{-1}, Latent heat of ice =3.5 \times 10^{5} \mathrm{Jkg}^{-1} ]

Option: 1

90


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

\mathrm{M_{1}=120g}

\mathrm{M_{2}=300g}

By the principle of calorimeter

Heat gain =Heat Lost

\mathrm{Q_{1}=Q_{2}}

\mathrm{xLf=m_{2}\Delta T_{lost}}

\mathrm{x\times 3.5\times10^{5}=300\times 4200\times 25 }

\mathrm{x=90g}

Posted by

SANGALDEEP SINGH

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