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  • A block of mass m is placed on a surface with a vertical cross section given by  <img alt="y=\frac{x^{3}}{6}." src="https://entrancecorner.oncodecogs.com/gif.latex?y%3D%5Cfrac%7Bx%5E%7B3%

A block of mass m is placed on a surface with a vertical cross section given by  y=\frac{x^{3}}{6}.    If the coefficient of friction is 0.5,the maximum height above the ground at which the block can be placed without slipping is :

Option: 1

\frac{1}{6}m


Option: 2

\frac{2}{3}m


Option: 3

\frac{1}{3}m


Option: 4

\frac{1}{2}m


Answers (1)

best_answer

As we learnt in

mgSin\theta=\mu mgCos\theta

tan\theta=\mu\:\:\:\:\:\:\:\:\:\:=> y=\frac{x^{3}}{6}

\frac{dy}{dx}= \frac{x^{2}}{2}=\frac{1}{2}\:\:\:\;\:x=1

y=\frac{1}{6}m

Posted by

Divya Prakash Singh

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