Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • A body is released from a height equal to the radius (r) of the earth. The velocity of the body when it strikes the surface of the earth will be : (Given g = acceleration due to gravity on t

A body is released from a height equal to the radius (r) of the earth. The velocity of the body when it strikes the surface of the earth will be :
(Given g = acceleration due to gravity on the earth.)

Option: 1

\sqrt gR


Option: 2

\sqrt\frac{gR}{2}


Option: 3

\sqrt{4 \mathrm{gR}}


Option: 4

\sqrt{2 \mathrm{gR}}


Answers (1)

best_answer

By energy conservation,

K_1+U_1=K_2+U_2

\begin{aligned} & \mathrm{O}-\frac{\mathrm{GMm}}{2 \mathrm{R}}=\frac{1}{2} \mathrm{mv}^2-\frac{\mathrm{GMm}}{\mathrm{R}} \\ & \mathrm{V}=\sqrt{\frac{\mathrm{GM}}{\mathrm{R}} \times \frac{\mathrm{R}}{\mathrm{R}}} \\ & \mathrm{V}=\sqrt{\mathrm{gR}} \end{aligned}              

Posted by

Anam Khan

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2025: 11 from Kota coaching centres among 24 students with 100 percentile
anam-khan

Low JEE Main rank? Explore alternative paths for engineering admission
anam-khan

Gender-gap in JEE Main 2025: Female participation remains around 31%, overall pool drops by 7.09%

Latest Question