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A box contains 10 screws, 3 of which are defective. Two screws are drawn at random with replacement. The probability that none of the two screws will be defective

Option: 1

100%


Option: 2

50%


Option: 3

49%


Option: 4

None of these


Answers (1)

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Box contains 3 defective screws and 7 non -defeclive scrows.

The required probability = (Prob. of 1 st screw non defective) X (Prob. of 2nd screw non-defective)

                                       \begin{aligned} & =\left(\frac{7}{10}\right) \cdot\left(\frac{7}{10}\right) \\ \\& =49 \% \end{aligned}

                                              {\therefore Draw is with replacement}

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shivangi.shekhar

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