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A box contains 2 washers, 3 nuts and 4 bolts. llems are drawn from the box at random one at a time without replacement. The probability of drawing 2 washers first followed by 3 nuts and subsequently the 4 bolts is

Option: 1

\frac{2}{315}


Option: 2

\frac{1}{630}


Option: 3

\frac{1}{1260}


Option: 4

\frac{1}{2520}


Answers (1)

best_answer

Given ,

                

The required probability 

=\left(\frac{2}{9} \times \frac{1}{8}\right) \times\left(\frac{3}{7} \times \frac{2}{6} \times \frac{1}{5}\right) \times\left(\frac{4}{4} \times \frac{3}{3} \times \frac{2}{2} \times \frac{1}{1}\right)

                                 =\frac{1}{36} \times \frac{1}{35}=\frac{1}{1260}

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mansi

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