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  • A box of mass 60kg is suspended by three massless strings as shown in fog. Find the tension in each string <img alt="T_A,T_B,T_C" src="http://entrancecorner.oncodecogs.com/gif.latex?T_A%2CT_B%

A box of mass 60kg is suspended by three massless strings as shown in fog. Find the tension in each string T_A,T_B,T_C (in N)

Option: 1

600,800,1000


Option: 2

800,1000,600


Option: 3

500,600,800


Option: 4

700,800,600


Answers (1)

best_answer

F.B.D of the block-

As the block is in equilibrium, the net force on the block must be zero-

\Rightarrow T_{c}=600 N

F.B.D of the knot (massless)-

As all massless bodies are in equilibrium, applying Lami's theorem for equilibrium of concurrent forces-

\frac{T_A}{\sin (90^{\circ}+37^{\circ})}= \frac{T_B}{\sin 90^{\circ}}= \frac{T_C}{\sin(180^{\circ}-37^{\circ}) }

T_C=600N

\frac{T_A}{\cos 37^{\circ}}= \frac{T_B}{1}=\frac{T_C}{\sin 37^{\circ}}

T_B=\frac{T_C}{\sin 37^{\circ}}= \frac{600}{3/5}= 1000N

T_A=T_B\cos 37^{\circ}\Rightarrow 1000*\frac{4}{5}= 800N

 

Posted by

himanshu.meshram

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