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  • At the bottom of a tank having liquid with refractive index, 'm' is a plane mirror. A small object '... Read more at: https://engineering.careers360.com/exams/jee-main/real-depth-and-ap

At the bottom of a tank having liquid with refractive index, 'm' is a plane mirror. A small object 'M' is situated at a height 'd' above the mirror. Object 'M' and its image in the mirror are visible to an observer who is 'O' vertically above M outside the liquid. The object 'M' and its image will appear to be separated by how much distance?

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Distance of object from mirror = d

For a plane mirror, the image forms at an equal distance behind the mirror.

Therefore, the distance of the image behind the mirror = d

Real separation between object and image = d + d = 2d

Since the observer is outside the liquid, all vertical distances appear reduced by the refractive index m.

Using the apparent depth relation: Apparent depth = Real depth / m

Therefore, the apparent separation between object and image = 2d/m

Posted by

Saniya Khatri

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