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A bullet of 10 g leaves the barrel of gun with a velocity of 600 m/s. If the barrel of gun is 50 cm long and mass of gun is 3 kg, then value of impulse supplied to the gun will be:

 

Option: 1

12 Ns


Option: 2

6 Ns


Option: 3

3 Ns

 


Option: 4

36 Ns


Answers (1)

best_answer

 By momentum conservation
 
\begin{aligned} & 0=3(-\mathrm{v})+0.01(600-\mathrm{v}) \\ & \mathrm{V} \sim 2 \mathrm{~m} / \mathrm{s} \\ & \text { Impulse on gun }=3 \times 2=6 \mathrm{Ns} \end{aligned}

Posted by

Devendra Khairwa

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