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A capacitor of capacitance C is charge to a potential V. The flux of the electric field through a closed surface enclosing the positive plate of the capacitor is :

Option: 1

Zero


Option: 2

\frac{\mathrm{CV}}{ \varepsilon_{0}}


Option: 3

\frac{2 \mathrm{CV}}{\varepsilon_{0}}


Option: 4

\frac{\mathrm{CV}}{2 \varepsilon_{0}}


Answers (1)

best_answer

\phi=\frac{\mathrm{q}}{\varepsilon_{0}}
\phi=\frac{\mathrm{CV}}{\varepsilon_{0}}

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Ritika Harsh

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