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A car is moving on convex bridge of radius r with velocity v for what maximum value of v car will loose contact with bridge
Option: 1
$\sqrt{2rg}$

Option: 2
$2 \sqrt {rg }$

Option: 3
$\sqrt {rg }$

Option: 4
$\frac{1}{2}\sqrt {rg }$

Answers (1)

best_answer

As we have learned

Reaction Road on Car When bridge is convex -

$F_{c}=mg\ cos\theta-R=\frac{mv^{2}}{r}$

$R=mg\ cos\theta-\frac{mv^{2}}{r}$

R = reaction

F_c= centripetal force

mg = weight

- wherein

$\theta=$ angle of R with centre

v = tangential velocity

$R = mg \cos \theta - \frac{mv^2}{r}$

$R_{max} = mg - \frac{mv^2}{r}$

To loose the contact R = 0

For $v_{max}, R_{max} = 0$

$mg - \frac{mv^2}{r } = 0$

$v_{max} = \sqrt {rg }$

Posted by

Shailly goel

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