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  • A car moves on a concave bridge of radius R then the maximum reaction force on the car will be: [ let the mass of the car be m]  Option:

A car moves on a concave bridge of radius R then the maximum reaction force on the car will be:

[ let the mass of the car be m]

 

Option: 1

mg


Option: 2

\frac{mv^{2}}{R}


Option: 3

mg - \frac{mv^{2}}{R}


Option: 4

mg + \frac{mv^{2}}{R}


Answers (1)

best_answer

 

 

 

 

As we learn

Reaction of Road on Car -

Centripetal force = R-mg\ cos\theta=\frac{mv^{2}}{r}

Reaction R =mg\ cos\theta+\frac{mv^{2}}{r}

R = reaction

V=velocity

r = radius

- wherein

It is a case when car moves on a concave bridge.

 

 maximum reactor will be at lowest point of bridge ,so

N = mg + \frac{mv^{2}}{R}

 

Posted by

mansi

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