Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa

A certain reaction has a heat capacity \mathrm{\left(C_p\right)} of  \mathrm{50 \mathrm{~J} / \mathrm{K}}. If \mathrm{500 \mathrm{~J}} of heat is added to the system, calculate the resulting temperature change \mathrm{(\Delta T)} of the reaction.

Option: 1

5 K


Option: 2

10 K


Option: 3

15 K


Option: 4

25 K


Answers (1)

best_answer

The relationship between heat (q), heat capacity \mathrm{ \left(C_p\right)}, and temperature change \mathrm{ (\Delta T)} is given by the equation:

\mathrm{ q=C_p \cdot \Delta T }

We are given $C_p=50 \mathrm{~J} / \mathrm{K}$ and $q=500 \mathrm{~J}$. Solving for $\Delta T$ :

\mathrm{ \Delta T=\frac{q}{C_p}=\frac{500 \mathrm{~J}}{50 \mathrm{~J} / \mathrm{K}}=10 \mathrm{~K} }
So, the correct answer is: B)\mathrm{ 10 \mathrm{~K}}

Posted by

Anam Khan

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

75% criteria for JEE Main 2025 not removed; eligibility criteria for admission to IITs
anam-khan

BTech Admissions 2025 LIVE: AEEE phase 1 exam date out, JEE Mains registration ongoing; BITSAT, VITEEE updates
anam-khan

JEE Main 2025 Eligibility Criteria: What is state code of eligibility? Here’s list of qualifying exams

Latest Question