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  • a circle with equation has centre (-2,6) and radius =<img alt="\sqrt{7}"

a circle with equation

x^2+y^2+4x+2fy+c=0 has centre (-2,6) and radius =\sqrt{7} . Find c.

Option: 1

31


Option: 2

33


Option: 3

35


Option: 4

37


Answers (1)

best_answer

as we learned

Centre of a circle and radius -

Fixed point in the circle is called the centre and fixed distance is called the radius.

-

Herem, g = -2 and f = -6,

 

Thus \sqrt{g^{2}+f^{2}-c}= \sqrt{7}\\*\\* \Rightarrow 4+36-c-7\\*\\* \Rightarrow c=33

 

 

Posted by

rishi.raj

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