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A committee of 6 people needs to be formed from a group of 15 individuals, including 8 men and 7 women. If the committee must have an equal number of men and women, and a specific man refuses to serve together with a specific woman, how many different committees can be formed?

Option: 1

600


Option: 2

400


Option: 3

900


Option: 4

700


Answers (1)

To calculate the number of different committees that can be formed from a group of 15 individuals, including 8 men and 7 women, with the condition that the committee must have an equal number of men and women and a specific man refuses to serve together with a specific woman, we can consider the following:

We need to choose 3 men and 3 women to form the committee. Since a specific man and woman cannot serve together, we need to exclude this pair from the selection.

To calculate the number of ways to choose 3 men out of the remaining 7 men (excluding the specific man) and 3 women out of the 6 women (excluding the specific woman), we use the combination formula.

The number of ways to choose 3 men from 7 is \mathrm{C(7,3)=35}, and the number of ways to choose 3 women from 6 is

\mathrm{C(6,3)=20}

Therefore, the total number of different committees that can be formed is \mathrm{35 \times 20=700.}

Hence, there are 700 different committees that can be formed from the group of 15 individuals, including 8 men and 7 women, with the condition of having an equal number of men and women and a specific man refusing to serve together with a specific woman.

Posted by

Ramraj Saini

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