Get Answers to all your Questions

header-bg qa

A compound 'A' on reaction with 'X' and 'Y' produces the same major product but different by product ' a ' and ' b '. Oxidation of ' a ' gives a substance produced by ants.

'X' and 'Y' respectively are

Option: 1

\mathrm{KMnO}_{4} / \mathrm{H}^{+} \text {and dil. } \mathrm{KMnO}_{4}, 273 \mathrm{~K}


Option: 2

\mathrm{KMnO}_{4} \text { (dilute), } 273 \mathrm{~K} \text { and } \mathrm{KMnO}_{4} / \mathrm{H}^{+}


Option: 3

\mathrm{KMnO}_{4} / \mathrm{H}^{+} \text {and } \mathrm{O}_{3}, \mathrm{H}_{2} \mathrm{O} / \mathrm{Zn}


Option: 4

\mathrm{O}_{3}, \mathrm{H}_{2} \mathrm{O} / \mathrm{Zn} \text { and } \mathrm{KMnO}_{4} / \mathrm{H}^{+}


Answers (1)

best_answer

Ants produces formic acid \text{(HCOOH)}.

\text{HCOOH} is formed from the oxidation of 'a' .

So, a should be \text{HCHO}

\text{(1) KMnO}_{4}/\text{H}^{+} will give \mathrm{CO}_2\left[\left(\mathrm{CH}_2=\mathrm{C}+\mathrm{R}\right)\right] \rightarrow \mathrm{CO}_2+\text{O=C R}

\mathrm{(2)\; dil.KMnO_{4},273K} will give alcohol.

\text { (3) } \mathrm{O}_3, \mathrm{H}_2 \mathrm{O} / \mathrm{Zn} will give \text { HCHO } and other compound.

Hence, the correct answer is option (4)

Posted by

manish

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE