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A compound microscope consists of an objective lens of focal length 1\; cm and an eye piece of focal length 5\; cm with a seperation of 10\; cm.The distance between an object and the objective lens, at which the strain on the eye is minimum is \frac{n}{40}cm The value of n is ______.
Option: 1 50
Option: 2 100
Option: 3 150
Option: 4 200

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\\ \text{Image by objective is formed at the focus of eye-piece} \\ \therefore$ For objective, $v=5, u, f=1 \mathrm{~cm}$

\begin{aligned} \frac{1}{5}-\frac{1}{u}=\frac{1}{1} \Rightarrow \frac{1}{5}-1=\frac{1}{u} \\ \therefore \quad|u|=\frac{5}{4} c m \Rightarrow|u|=\frac{50}{40} c m \\ \therefore \quad n=50 \end{aligned}

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Deependra Verma

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