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  • A conducting rod of length of l = 0.5 m slides at constant velocity 'v = 3 m/s' on two parallel conducting rails, placed in a uniform and constant magnetic field B = 5T perpendicular to the

A conducting rod of length of l = 0.5 m slides at constant velocity 'v = 3 m/s' on two parallel conducting rails, placed in a uniform and constant magnetic field B = 5T perpendicular to the plane of the rails as shown in the figure. A resistance R = 10 ohm is connected between the two ends of the rail. Find the electric power dissipated in the resistor.

 

Option: 1

4 W


Option: 2

4.825 W


Option: 3

5.625 W


Option: 4

6.325 W


Answers (1)

best_answer

 

 

\begin{array}{l}{P=\frac{B^{2} v^{2} l^{2}}{R}}\\ \\ {P=\frac{(5)^{2}(3)^{2}(0.5)^{2}}{10}} \\ \\ {P=5.625 W}\end{array}

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manish painkra

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