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  • A conducting rod of length of l = 2 m slides at constant velocity 'v = 5 m/s' on two parallel conducting rails, placed in a uniform and constant magnetic field B = 0.5T perpendicu

A conducting rod of length of l = 2 m slides at constant velocity 'v = 5 m/s' on two parallel conducting rails, placed in a uniform and constant magnetic field B = 0.5T perpendicular to the plane of the rails as shown in the figure. Find resistance R which is connected between the two ends of the rail. If the electric power dissipated in the resistor is 20 W

 

 

Option: 1

1 \Omega


Option: 2

1.25 \ \Omega


Option: 3

1.5 \ \Omega


Option: 4

1.75 \ \Omega


Answers (1)

best_answer

 

 

\begin{array}{l}{P=\frac{B^{2} l^{2} v^{2}}{R}}\\ \\ {R=\frac{B^{2} l^{2} v^{2}}{P}} \\ \\ {R=\frac{(0.5)^{2} *(2)^{2} *(5)^{2}}{20}}\\ \\ {R=1.25 \Omega}\end{array}

Posted by

Ritika Jonwal

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