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  • A conductor of length 1 m and resistance 0.5 <img alt="\Omega" s

A conductor of length 1 m and resistance 0.5 \Omega  is moving in a  uniform magnetic field of intensity 5 \times 10^{-4}T  .The velocity of the conductor is 4 m/s and is directed perpendicular to the field.

The induced current in conductor would be 

Option: 1

4 mA 


Option: 2

4 \mu A


Option: 3

8 mA 


Option: 4

8\mu A


Answers (1)

best_answer

As we have learned

Induced Current -

I= \frac{\varepsilon }{R}= \frac{Blv}{R}

-

 

 Induced emf \varepsilon = Blv

 induced current i = \frac{\varepsilon }{R}

i = \frac{Blv }{R}

i = \frac{5 \times 10^{-4}\times 1\times 4 }{0.5}\times 10

i =4 mA

 

Posted by

HARSH KANKARIA

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