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A convex lens has power \mathrm{P}. It is cut into two halves along its principal axis. Further one piece (out of the two halves) is cut into two halves perpendicular to the principal axis (as shown in figures). Choose the incorrect option for the reported pieces.

Option: 1

\mathrm{\text{Power of}\, \, L_{1}= \frac{P}{2}}


Option: 2

\mathrm{\text{Power of}\, \, L_{2}= \frac{P}{2}}


Option: 3

\mathrm{\text{Power of}\, \, L_{3}= \frac{P}{2}}


Option: 4

\mathrm{\text{Power of}\, \, L_{1}= P}


Answers (1)

best_answer


Len's maker's formula.
\mathrm{P= \frac{1}{f}= \left ( \frac{\mu_g}{\mu_m}-1 \right )\left ( \frac{1}{R_{1}}-\frac{1}{R_{2}} \right )}

For convex Lens
\mathrm{R_{1}= +R,\: R_{2}= -R}
\mathrm{P= \left ( \frac{\mu_g}{\mu_m} -1\right )\left ( \frac{2}{R} \right )}.

for \mathrm{L_{1},R_{1} \& R_{2}} remain the same as the original Lens

\mathrm{\therefore }  even after cutting,
\mathrm{L_{1} } , power will be the same as \mathrm{P }. (original Lens). & for \mathrm{L_{2} \, \&\, L _{3} } power become half.

The correct answer is (1)
 

Posted by

Rishi

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