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A copper block of mass \mathrm{5.0kg} is heated to a temperature of \mathrm{500^{\circ}C} and is placed on a large ice block. What is the maximum amount of ice that can melt? [ Specific heat of copper : \mathrm{0.39J g^{-1}}\mathrm{^{\circ}C^{-1}} and latent heat of fusion of water : \mathrm{335}\mathrm{Jg^{-1}} ]

Option: 1

\mathrm{1.5kg}


Option: 2

\mathrm{5.8kg}


Option: 3

\mathrm{2.9kg}


Option: 4

\mathrm{3.8kg}


Answers (1)

best_answer

\mathrm{m= 5kg}

\mathrm{C_{cu}= 0.39Jg^{-1} {^{\circ}C^{-1}}}

\mathrm{L_{water}= 335Jg^{-1}}

By the principle of calorimeter,

Heat lost by copper =Heat gained by ice

\mathrm{m_{1} C_{\text {cu }} \Delta T =m_{2} L_{\text {water }}}\\

\mathrm{5000 \times 0.39 \times(500-0) =m_{2} \times 335}\\

\mathrm{m_{2} =\frac{9.75 \times 10^{5} }{335}g}\\

\mathrm{m_{2} =2.9 \mathrm{~kg}}

Hence the correct answer is option 3

Posted by

shivangi.bhatnagar

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