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A cricketer can throw a ball to a maximum horizontal distance of 100 m . How much high above the ground can the cricketer throw the same ball ? (Answer in meters)

Option: 1

50


Option: 2

60


Option: 3

75


Option: 4

80


Answers (1)

best_answer

As we have learned

Horizontal Range -

Horizontal distance travelled by projectile from the point of projectile to the point on ground where its hits.

R=\frac{u^{2}\sin 2\Theta }{g}

 

 

 

- wherein

Special case of horizontal range

For man horizontal range.

\Theta = 45^{0}

R_{max}=\frac{u^{2}\sin 2 (45) }{g}=\frac{u^{2}\times 1}{g}=\frac{u^{2}}{g}

 

 R = \frac{u^2\sin 2 \theta }{g} 

R is maximum , when \theta = 45 \degree

 R^{max} = \frac{u^2}{g}= 100 \Rightarrow u^2 = 1000 ......(1)

H = \frac{u^2}{2g}= 50 m

 

 

 

 

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mansi

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