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A detective uses a converging lens of focal length 12 cm to examine the fine details of some cloth fibers found at the scene of a crime. What is the magnification for relaxed eye viewing?

Option: 1 1.2

Option: 2 2.5

Option: 3 0.48

Option: 4 2.1

Answers (1)

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m_{\infty }=\left(\frac{D}{f}\right)_{min}

 

when the object lies at infinity, the eye is most relaxed. Therefore, magnification for relaxed eye viewing,

M=\frac{D}{f}=\frac{25}{12}=2.1

Posted by

Pankaj Sanodiya

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