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  • A domain in ferromagnetic substance is in the form of a cube of side length 1. If it contains <img alt="8\tim

A domain in ferromagnetic substance is in the form of a cube of side length 1\mu m. If it contains 8\times 10^{10} atoms and each atoms dipole has dipole moment of 9\times 10^{-24} A m^2 then magnetization of the domain is 

Option: 1

7.2\times 10^{5}Am^{-1}


Option: 2

7.2\times 10^{3}Am^{-1}


Option: 3

7.2\times 10^{7}Am^{-1}


Option: 4

7.2\times 10^{12}Am^{-1}


Answers (1)

best_answer

The intensity of magnetisation -

It is defined as the Pole strength per unit cross-sectional area of the substance or the induced dipole moment per unit volume.

 

 The volume of cubic domain is 

V = (10^{-6}m)^3 = 10^{-18} m^3 \\*m_{net} = 8\times 10^{10}\times 9\times 10^{-24} Am^2 \\*m_{net} = 72\times 10^{-14} A m^2

Magnetisation (M) = \frac{m_{net}}{domain\;Volume} = \frac{72\times 10^{-14}}{10^{-18}} = 7.2\times 10^{5} Am^{-1}

 

Posted by

Gaurav

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