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A flask contains argon and oxygen in the ratio of 3:2 in mass and the mixture is kept at \mathrm{27C^{\circ}}. The ratio of their average kinetic energy per molecule respectively will be :

Option: 1

3:2


Option: 2

9:4


Option: 3

2:3


Option: 4

1:1


Answers (1)

best_answer

\mathrm{T=300 \mathrm{~K}}
\mathrm{\frac{m_{A r}}{m_{\mathrm{0}_{2}}}=\frac{3}{2}}
\mathrm{Avg. K E\: per\: molecule =\frac{3}{2} K_{B} T}
The avg. KE per molecule is & independent of mass
\therefore At a given temperáture,it will be same for Argon and Oxygen.
 
The correct option is (4)

Posted by

Divya Prakash Singh

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