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  • A force <img alt="\mathrm{\bar{F}=\left ( 2+3x \right )\hat{i}}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%7B%5Cbar%7BF%7D%3D%5Cleft%20%28%202&plus;3x%20%5Cright%20%29%5Cha

A force \mathrm{\bar{F}=\left ( 2+3x \right )\hat{i}} acts on a particle in the x direction where F is in newton and x is in meter. The work done by this force during a displacement from \mathrm{x = 0\: to \: x = 4 m}, is ______ J.

Option: 1

32


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

\mathrm{\bar{F}=\left ( 2+3x \right )i}

\mathrm{w=\int_{0}^{4}F.dx=\int_{0}^{4}\left ( 2+3x \right ).dx}

\mathrm{w=\left ( 2x+\frac{3x^{2}}{2} \right )^{4}=\left ( 8+24 \right )}

\mathrm{w=32\: J}

Posted by

Rakesh

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