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A gas at pressure \mathrm{P_{0}} is contained in a vessel. If the masses of all the molecules are halved and their speeds doubled, the resulting pressure would be

Option: 1

\quad 4 \mathrm{P}_{0}


Option: 2

2 \mathrm{P}_{0}


Option: 3

\mathrm{P}_{0}


Option: 4

\frac{P_{0}}{2}


Answers (1)

best_answer

\quad \mathrm{P}=\frac{1}{3} \frac{\mathrm{mn}}{\mathrm{V}}\left(\mathrm{V}^{2}{ }_{\mathrm{rms}}\right) where \mathrm{m}= mass of one gas molecules

\mathrm{n}=  total no. of gas molecules

\mathrm{i.e, P \propto m \, and \, P \propto V rms}

Here m is halved and V_{\text {rms }} is doubled

\therefore pressure will be doubled

Hence, (B) is correct

Posted by

manish painkra

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