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  • A gas of hydrogen like atoms can absorb radiations of 68 eV. Consequently, the atoms emit radiations of only three different wavelengths. All the wavelengths are equal or smaller than that of the a

A gas of hydrogen like atoms can absorb radiations of 68 eV. Consequently, the atoms emit radiations of only three different wavelengths. All the wavelengths are equal or smaller than that of the absorbed photon. Then the gas atoms is:

Option: 1

Li


Option: 2

Be
 


Option: 3

B


Option: 4

C


Answers (1)

Since three radiations are emitted, therefore , the final excited state of the gas is n = 3.
The initial state of the gas atoms is n = 2

13.6 Z^2\left[\frac{1}{2^2}-\frac{1}{3^2}\right]=68

or         13.6 Z^2\left[\frac{5}{36}\right\rfloor=68

or     Z=6

Posted by

Sumit Saini

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