# A helicopter rises from rest on the ground vertically upwards with a constant acceleration $g$. A food packet is dropped from the helicopter when it is at a height h. The time taken by the packet to reach the ground is close to [ $g$ is the acceleration due to gravity ]: Option: 1   Option: 2 Option: 3 Option: 4

$\begin{array}{l} \Rightarrow \sqrt{4 \mathrm{gh}}=\sqrt{2 \mathrm{gh}}+\mathrm{gt} \\ \\ \Rightarrow \mathrm{t}=\sqrt{\frac{4 \mathrm{~h}}{\mathrm{~g}}}-\sqrt{\frac{2 \mathrm{~h}}{\mathrm{~g}}} \Rightarrow 3.4 \sqrt{\frac{\mathrm{h}}{\mathrm{g}}} \end{array}$

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