Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • A juggler throws balls vertically upwards with same initial velocity in air. When the first ball reaches its highest position, he throws the next ball. Assuming the juggler throws <img alt="\mathrm

A juggler throws balls vertically upwards with same initial velocity in air. When the first ball reaches its highest position, he throws the next ball. Assuming the juggler throws \mathrm{n} balls per second, the maximum height the balls can reach is

 

Option: 1

\mathrm{g} / 2 \mathrm{n}


Option: 2

\mathrm{g} / \mathrm{n}


Option: 3

\mathrm{2\: gn}


Option: 4

\mathrm{g / 2 n^{2}}


Answers (1)

best_answer

\mathrm{V=u+at}

If n balls are thrown in 1 second then time between two consecutive ball is \mathrm{\frac{1}{n}} i.e time taken by the first ball when it reaches the highest position is \mathrm{\frac{1}{n}s}

\mathrm{0=u+(-g)+\left(\frac{1}{n}\right) }

\mathrm{u=\frac{9}{n} \rightarrow(1) }

\mathrm{v^2=u^2+2 a s }

\mathrm{0=\frac{g^2}{n^2}+2(-g) h ; h=\frac{9}{2 n^2}}

Hence 4 is correct option.

Posted by

Pankaj Sanodiya

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2025: Most important chapters for physics, chemistry, mathematics to score good marks
anam-khan

JEE Main 2025 session 2 dates clash with ISC, PSEB 12th exams; no impact on major science subjects
anam-khan

Delhi police EOW books FIITJEE for fraud; 192 complaints filed

Latest Question